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C – Increment and decrement
I am trying to learn some C and I was doing some tests with the ++ and -++ operators.
Here’s what I wrote:
void increment(int a)
{
a++;
}
void decrement(int a)
{
a–;
}
int main()
{
int i = 1;
i++;
i–;
printf(“i= %d”, i);
}
But the program outputs i= 2. Why?
A:
You cannot modify variables in other functions. The variable i is read only. So there is no point doing i++.
The compiler optimizes it by inserting the value of the variable in each function.
Similarly if you want to assign a new value after incrementing the value, it has to be done inside the function.
In this case:
void increment(int a)
{
a++;
a = 4;
}
A:
i++ and i– are called post-increment and pre-decrement, respectively. These operations are done before, and after, the memory assignment, respectively. Therefore, the code never assigns 4 to i.
To change the value, you need to change the value inside the function.
void increment(int a) {
a = a + 1;
}
A:
Please read up on functions before attempting to “try to understand” them.
Your code does exactly what it says: it increments the variable, it doesn’t print anything. Why? Because increment is a non-void function, and as soon as it starts modifying i, it returns.
What you’re looking for, is something like
void foo (int i)
{
i++;
printf(“Hello World”);
}
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